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44 lines (37 loc) · 990 Bytes
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package leetcode.string;
/**
* 有效的字母异位词
* 给定两个字符串 s 和 t ,编写一个函数来判断 t 是否是 s 的一个字母异位词。
*
* 示例 1:
*
* 输入: s = "anagram", t = "nagaram"
* 输出: true
* 示例 2:
*
* 输入: s = "rat", t = "car"
* 输出: false
*/
public class IsAnagram {
public static void main(String[] args) {
String s = "anagram", t = "nagaram";
System.out.println(isAnagram(s, t));
}
public static boolean isAnagram(String s, String t) {
if (s.length() != t.length()) {
return false;
}
// 代表26个字母
int[] srray = new int[26];
int[] trray = new int[26];
for (int i = 0; i < s.length(); i++) {
srray[s.charAt(i)-97]++;
trray[t.charAt(i)-97]++;
}
for (int i = 0; i < 26; i++) {
if (srray[i] != trray[i])
return false;
}
return true;
}
}